Results
\(\text{BER}(E_b/N_0) \ [dB]\)
The results seem to be correct - as \(\frac{E_b}{N_0}\) increases, \(\text{BER}\) decreases.
\(\text{BER}(E_b/N_0) \ [dB]\)
The results seem to be correct - as \(\frac{E_b}{N_0}\) increases, \(\text{BER}\) decreases.